(d^4-16)y=0

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Solution for (d^4-16)y=0 equation:


Simplifying
(d4 + -16) * y = 0

Reorder the terms:
(-16 + d4) * y = 0

Reorder the terms for easier multiplication:
y(-16 + d4) = 0
(-16 * y + d4 * y) = 0

Reorder the terms:
(d4y + -16y) = 0
(d4y + -16y) = 0

Solving
d4y + -16y = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '16y' to each side of the equation.
d4y + -16y + 16y = 0 + 16y

Combine like terms: -16y + 16y = 0
d4y + 0 = 0 + 16y
d4y = 0 + 16y
Remove the zero:
d4y = 16y

Divide each side by 'y'.
d4 = 16

Simplifying
d4 = 16

Reorder the terms:
-16 + d4 = 16 + -16

Combine like terms: 16 + -16 = 0
-16 + d4 = 0

Factor a difference between two squares.
(4 + d2)(-4 + d2) = 0

Factor a difference between two squares.
(4 + d2)((2 + d)(-2 + d)) = 0

Subproblem 1

Set the factor '(4 + d2)' equal to zero and attempt to solve: Simplifying 4 + d2 = 0 Solving 4 + d2 = 0 Move all terms containing d to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + d2 = 0 + -4 Combine like terms: 4 + -4 = 0 0 + d2 = 0 + -4 d2 = 0 + -4 Combine like terms: 0 + -4 = -4 d2 = -4 Simplifying d2 = -4 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + d)' equal to zero and attempt to solve: Simplifying 2 + d = 0 Solving 2 + d = 0 Move all terms containing d to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + d = 0 + -2 Combine like terms: 2 + -2 = 0 0 + d = 0 + -2 d = 0 + -2 Combine like terms: 0 + -2 = -2 d = -2 Simplifying d = -2

Subproblem 3

Set the factor '(-2 + d)' equal to zero and attempt to solve: Simplifying -2 + d = 0 Solving -2 + d = 0 Move all terms containing d to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + d = 0 + 2 Combine like terms: -2 + 2 = 0 0 + d = 0 + 2 d = 0 + 2 Combine like terms: 0 + 2 = 2 d = 2 Simplifying d = 2

Solution

d = {-2, 2}

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